Optimal. Leaf size=1066 \[ \frac{(2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{16 c^{3/2} g^3 (e f-d g)^3}-\frac{\left (c f^2-b g f+a g^2\right )^{3/2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^2}{g^3 (e f-d g)^3}-\frac{\left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{c x^2+b x+a} e^2}{8 c g^2 (e f-d g)^3}+\frac{\left (c x^2+b x+a\right )^{3/2} e}{(e f-d g)^2 (f+g x)}-\frac{3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e}{8 \sqrt{c} g^3 (e f-d g)^2}+\frac{3 (2 c f-b g) \sqrt{c f^2-b g f+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e}{2 g^3 (e f-d g)^2}+\frac{3 (4 c f-3 b g-2 c g x) \sqrt{c x^2+b x+a} e}{4 g^2 (e f-d g)^2}+\frac{\left (c x^2+b x+a\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{3 \sqrt{c} (2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right )}{2 g^3 (e f-d g)}-\frac{3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right )}{8 g^3 (e f-d g) \sqrt{c f^2-b g f+a g^2}}+\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{c x^2+b x+a}}{8 c (e f-d g)^3}-\frac{3 (4 c f-b g+2 c g x) \sqrt{c x^2+b x+a}}{4 g^2 (e f-d g) (f+g x)}-\frac{(2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right )}{16 c^{3/2} (e f-d g)^3 e}+\frac{\left (c d^2-b e d+a e^2\right )^{3/2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b e d+a e^2} \sqrt{c x^2+b x+a}}\right )}{(e f-d g)^3 e} \]
[Out]
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Rubi [A] time = 1.7059, antiderivative size = 1066, normalized size of antiderivative = 1., number of steps used = 30, number of rules used = 9, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.31, Rules used = {960, 734, 814, 843, 621, 206, 724, 732, 812} \[ \frac{(2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e^2}{16 c^{3/2} g^3 (e f-d g)^3}-\frac{\left (c f^2-b g f+a g^2\right )^{3/2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e^2}{g^3 (e f-d g)^3}-\frac{\left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{c x^2+b x+a} e^2}{8 c g^2 (e f-d g)^3}+\frac{\left (c x^2+b x+a\right )^{3/2} e}{(e f-d g)^2 (f+g x)}-\frac{3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right ) e}{8 \sqrt{c} g^3 (e f-d g)^2}+\frac{3 (2 c f-b g) \sqrt{c f^2-b g f+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right ) e}{2 g^3 (e f-d g)^2}+\frac{3 (4 c f-3 b g-2 c g x) \sqrt{c x^2+b x+a} e}{4 g^2 (e f-d g)^2}+\frac{\left (c x^2+b x+a\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{3 \sqrt{c} (2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right )}{2 g^3 (e f-d g)}-\frac{3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b g f+a g^2} \sqrt{c x^2+b x+a}}\right )}{8 g^3 (e f-d g) \sqrt{c f^2-b g f+a g^2}}+\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{c x^2+b x+a}}{8 c (e f-d g)^3}-\frac{3 (4 c f-b g+2 c g x) \sqrt{c x^2+b x+a}}{4 g^2 (e f-d g) (f+g x)}-\frac{(2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{c x^2+b x+a}}\right )}{16 c^{3/2} (e f-d g)^3 e}+\frac{\left (c d^2-b e d+a e^2\right )^{3/2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b e d+a e^2} \sqrt{c x^2+b x+a}}\right )}{(e f-d g)^3 e} \]
Antiderivative was successfully verified.
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Rule 960
Rule 734
Rule 814
Rule 843
Rule 621
Rule 206
Rule 724
Rule 732
Rule 812
Rubi steps
\begin{align*} \int \frac{\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)^3} \, dx &=\int \left (\frac{e^3 \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^3 (d+e x)}-\frac{g \left (a+b x+c x^2\right )^{3/2}}{(e f-d g) (f+g x)^3}-\frac{e g \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)^2}-\frac{e^2 g \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^3 (f+g x)}\right ) \, dx\\ &=\frac{e^3 \int \frac{\left (a+b x+c x^2\right )^{3/2}}{d+e x} \, dx}{(e f-d g)^3}-\frac{\left (e^2 g\right ) \int \frac{\left (a+b x+c x^2\right )^{3/2}}{f+g x} \, dx}{(e f-d g)^3}-\frac{(e g) \int \frac{\left (a+b x+c x^2\right )^{3/2}}{(f+g x)^2} \, dx}{(e f-d g)^2}-\frac{g \int \frac{\left (a+b x+c x^2\right )^{3/2}}{(f+g x)^3} \, dx}{e f-d g}\\ &=\frac{\left (a+b x+c x^2\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{e \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)}-\frac{e^2 \int \frac{(b d-2 a e+(2 c d-b e) x) \sqrt{a+b x+c x^2}}{d+e x} \, dx}{2 (e f-d g)^3}+\frac{e^2 \int \frac{(b f-2 a g+(2 c f-b g) x) \sqrt{a+b x+c x^2}}{f+g x} \, dx}{2 (e f-d g)^3}-\frac{(3 e) \int \frac{(b+2 c x) \sqrt{a+b x+c x^2}}{f+g x} \, dx}{2 (e f-d g)^2}-\frac{3 \int \frac{(b+2 c x) \sqrt{a+b x+c x^2}}{(f+g x)^2} \, dx}{4 (e f-d g)}\\ &=\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{8 c (e f-d g)^3}+\frac{3 e (4 c f-3 b g-2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g)^2}-\frac{3 (4 c f-b g+2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g) (f+g x)}-\frac{e^2 \left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{a+b x+c x^2}}{8 c g^2 (e f-d g)^3}+\frac{\left (a+b x+c x^2\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{e \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)}+\frac{\int \frac{\frac{1}{2} \left (4 c e (b d-2 a e)^2-d (2 c d-b e) \left (4 b c d-b^2 e-4 a c e\right )\right )-\frac{1}{2} (2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right ) x}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{8 c (e f-d g)^3}-\frac{e^2 \int \frac{\frac{1}{2} \left (4 c g (b f-2 a g)^2-f (2 c f-b g) \left (4 b c f-b^2 g-4 a c g\right )\right )-\frac{1}{2} (2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right ) x}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{8 c g^2 (e f-d g)^3}+\frac{(3 e) \int \frac{c \left (3 b^2 f g+4 a c f g-4 b \left (c f^2+a g^2\right )\right )-c \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) x}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{8 c g^2 (e f-d g)^2}+\frac{3 \int \frac{4 b c f-b^2 g-4 a c g+4 c (2 c f-b g) x}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{8 g^2 (e f-d g)}\\ &=\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{8 c (e f-d g)^3}+\frac{3 e (4 c f-3 b g-2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g)^2}-\frac{3 (4 c f-b g+2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g) (f+g x)}-\frac{e^2 \left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{a+b x+c x^2}}{8 c g^2 (e f-d g)^3}+\frac{\left (a+b x+c x^2\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{e \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)}+\frac{\left (c d^2-b d e+a e^2\right )^2 \int \frac{1}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{e (e f-d g)^3}-\frac{\left ((2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right )\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{16 c e (e f-d g)^3}+\frac{(3 c (2 c f-b g)) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{2 g^3 (e f-d g)}+\frac{\left (3 e (2 c f-b g) \left (c f^2-b f g+a g^2\right )\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{2 g^3 (e f-d g)^2}-\frac{\left (e^2 \left (c f^2-b f g+a g^2\right )^2\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{g^3 (e f-d g)^3}+\frac{\left (e^2 (2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right )\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{16 c g^3 (e f-d g)^3}-\frac{\left (3 e \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right )\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{8 g^3 (e f-d g)^2}-\frac{\left (3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right )\right ) \int \frac{1}{(f+g x) \sqrt{a+b x+c x^2}} \, dx}{8 g^3 (e f-d g)}\\ &=\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{8 c (e f-d g)^3}+\frac{3 e (4 c f-3 b g-2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g)^2}-\frac{3 (4 c f-b g+2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g) (f+g x)}-\frac{e^2 \left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{a+b x+c x^2}}{8 c g^2 (e f-d g)^3}+\frac{\left (a+b x+c x^2\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{e \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)}-\frac{\left (2 \left (c d^2-b d e+a e^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac{-b d+2 a e-(2 c d-b e) x}{\sqrt{a+b x+c x^2}}\right )}{e (e f-d g)^3}-\frac{\left ((2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{8 c e (e f-d g)^3}+\frac{(3 c (2 c f-b g)) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{g^3 (e f-d g)}-\frac{\left (3 e (2 c f-b g) \left (c f^2-b f g+a g^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{g^3 (e f-d g)^2}+\frac{\left (2 e^2 \left (c f^2-b f g+a g^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{g^3 (e f-d g)^3}+\frac{\left (e^2 (2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{8 c g^3 (e f-d g)^3}-\frac{\left (3 e \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{4 g^3 (e f-d g)^2}+\frac{\left (3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac{-b f+2 a g-(2 c f-b g) x}{\sqrt{a+b x+c x^2}}\right )}{4 g^3 (e f-d g)}\\ &=\frac{\left (8 c^2 d^2+b^2 e^2-2 c e (5 b d-4 a e)-2 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{8 c (e f-d g)^3}+\frac{3 e (4 c f-3 b g-2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g)^2}-\frac{3 (4 c f-b g+2 c g x) \sqrt{a+b x+c x^2}}{4 g^2 (e f-d g) (f+g x)}-\frac{e^2 \left (8 c^2 f^2+b^2 g^2-2 c g (5 b f-4 a g)-2 c g (2 c f-b g) x\right ) \sqrt{a+b x+c x^2}}{8 c g^2 (e f-d g)^3}+\frac{\left (a+b x+c x^2\right )^{3/2}}{2 (e f-d g) (f+g x)^2}+\frac{e \left (a+b x+c x^2\right )^{3/2}}{(e f-d g)^2 (f+g x)}-\frac{(2 c d-b e) \left (8 c^2 d^2-b^2 e^2-4 c e (2 b d-3 a e)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{16 c^{3/2} e (e f-d g)^3}+\frac{3 \sqrt{c} (2 c f-b g) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{2 g^3 (e f-d g)}+\frac{e^2 (2 c f-b g) \left (8 c^2 f^2-b^2 g^2-4 c g (2 b f-3 a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{16 c^{3/2} g^3 (e f-d g)^3}-\frac{3 e \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{8 \sqrt{c} g^3 (e f-d g)^2}+\frac{\left (c d^2-b d e+a e^2\right )^{3/2} \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b d e+a e^2} \sqrt{a+b x+c x^2}}\right )}{e (e f-d g)^3}+\frac{3 e (2 c f-b g) \sqrt{c f^2-b f g+a g^2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{2 g^3 (e f-d g)^2}-\frac{e^2 \left (c f^2-b f g+a g^2\right )^{3/2} \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{g^3 (e f-d g)^3}-\frac{3 \left (8 c^2 f^2+b^2 g^2-4 c g (2 b f-a g)\right ) \tanh ^{-1}\left (\frac{b f-2 a g+(2 c f-b g) x}{2 \sqrt{c f^2-b f g+a g^2} \sqrt{a+b x+c x^2}}\right )}{8 g^3 (e f-d g) \sqrt{c f^2-b f g+a g^2}}\\ \end{align*}
Mathematica [A] time = 3.76584, size = 1036, normalized size = 0.97 \[ \frac{1}{4} \left (-\frac{\left ((2 c f-b g) \left (8 c^2 f^2-b^2 g^2+4 c g (3 a g-2 b f)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )+2 \sqrt{c} \left (8 c \tanh ^{-1}\left (\frac{-b f-2 c x f+2 a g+b g x}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right ) \left (c f^2+g (a g-b f)\right )^{3/2}+g \sqrt{a+x (b+c x)} \left (4 f (g x-2 f) c^2-2 g (-5 b f+4 a g+b g x) c-b^2 g^2\right )\right )\right ) e^2}{4 c^{3/2} g^3 (d g-e f)^3}+\frac{4 (a+x (b+c x))^{3/2} e}{(e f-d g)^2 (f+g x)}-\frac{3 \left (\left (8 c^2 f^2+b^2 g^2+4 c g (a g-2 b f)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )+2 \sqrt{c} \left (g \sqrt{a+x (b+c x)} (-4 c f+3 b g+2 c g x)+2 (2 c f-b g) \sqrt{c f^2+g (a g-b f)} \tanh ^{-1}\left (\frac{-b f-2 c x f+2 a g+b g x}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right )\right )\right ) e}{2 \sqrt{c} g^3 (e f-d g)^2}+\frac{2 (a+x (b+c x))^{3/2}}{(e f-d g) (f+g x)^2}+\frac{3 \left (\frac{(b g-2 c f) (a+x (b+c x))^{3/2}}{f+g x}-\frac{\left (2 f (2 f-g x) c^2+g (-5 b f+2 a g+b g x) c+b^2 g^2\right ) \sqrt{a+x (b+c x)}}{g^2}+\frac{4 \sqrt{c} (2 c f-b g) \left (c f^2+g (a g-b f)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )+\left (8 c^2 f^2+b^2 g^2+4 c g (a g-2 b f)\right ) \sqrt{c f^2+g (a g-b f)} \tanh ^{-1}\left (\frac{-b f-2 c x f+2 a g+b g x}{2 \sqrt{c f^2+g (a g-b f)} \sqrt{a+x (b+c x)}}\right )}{2 g^3}\right )}{(e f-d g) \left (c f^2+g (a g-b f)\right )}+\frac{-(2 c d-b e) \left (8 c^2 d^2-b^2 e^2+4 c e (3 a e-2 b d)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )-2 \sqrt{c} \left (8 c \tanh ^{-1}\left (\frac{-b d-2 c x d+2 a e+b e x}{2 \sqrt{c d^2+e (a e-b d)} \sqrt{a+x (b+c x)}}\right ) \left (c d^2+e (a e-b d)\right )^{3/2}+e \sqrt{a+x (b+c x)} \left (4 d (e x-2 d) c^2-2 e (-5 b d+4 a e+b e x) c-b^2 e^2\right )\right )}{4 c^{3/2} (e f-d g)^3 e}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.356, size = 15927, normalized size = 14.9 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{2} + b x + a\right )}^{\frac{3}{2}}}{{\left (e x + d\right )}{\left (g x + f\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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